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# RSX 112 20-05-2025
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## La Cryptographie
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Identifié la personne, envoyer un message de manière intègre.
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Primitive chyptographique, qui va chrypter, chiffrer, etc un msg
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Primitive chyptographique : Procécus de chiffrement et de chiffrement
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## TP 5 :
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mdp 1 -> 1 sec
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mdp 2 -> 1 sec
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mdp 3 -> 1 sec
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mdp 4 -> 10 sec
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mdp 5 -> 3 min
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mdp 6 -> plusieurs heures potentiel.
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┌──(nk㉿nk-kali)-[~/Zip-Files]
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└─$ fcrackzip -vul 1 file-A-1.zip
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found file 'user_credentials_1.txt', (size cp/uc 271/ 442, flags 9, chk 3c3d)
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found file 'user_credentials_2.txt', (size cp/uc 270/ 442, flags 9, chk 3c3d)
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found file 'user_credentials_3.txt', (size cp/uc 272/ 445, flags 9, chk 3c3d)
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PASSWORD FOUND!!!!: pw == B
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┌──(nk㉿nk-kali)-[~/Zip-Files]
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└─$ fcrackzip -vul 2 file-A-2.zip
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found file 'user_credentials_4.txt', (size cp/uc 267/ 437, flags 9, chk 3c3d)
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found file 'user_credentials_5.txt', (size cp/uc 259/ 433, flags 9, chk 3c3d)
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found file 'user_credentials_6.txt', (size cp/uc 271/ 442, flags 9, chk 3c3d)
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PASSWORD FOUND!!!!: pw == R2
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┌──(nk㉿nk-kali)-[~/Zip-Files]
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└─$ fcrackzip -vul 3 file-A-3.zip
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found file 'user_credentials_7.txt', (size cp/uc 271/ 443, flags 9, chk 3c3d)
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found file 'user_credentials_8.txt', (size cp/uc 266/ 435, flags 9, chk 3c3d)
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found file 'user_credentials_9.txt', (size cp/uc 264/ 437, flags 9, chk 3c3d)
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PASSWORD FOUND!!!!: pw == 0B1
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┌──(nk㉿nk-kali)-[~/Zip-Files]
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└─$ fcrackzip -vul 4 file-A-4.zip
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found file 'user_credentials_10.txt', (size cp/uc 250/ 420, flags 9, chk 3c3d)
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found file 'user_credentials_11.txt', (size cp/uc 252/ 422, flags 9, chk 3c3d)
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found file 'user_credentials_12.txt', (size cp/uc 261/ 433, flags 9, chk 3c3d)
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checking pw W&t~
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PASSWORD FOUND!!!!: pw == Y0Da
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┌──(nk㉿nk-kali)-[~/Zip-Files]
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└─$ fcrackzip -vul 5 file-A-5.zip
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found file 'user_credentials_13.txt', (size cp/uc 279/ 452, flags 9, chk 3c3d)
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found file 'user_credentials_14.txt', (size cp/uc 256/ 427, flags 9, chk 3c3d)
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found file 'user_credentials_15.txt', (size cp/uc 264/ 434, flags 9, chk 3c3d)
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checking pw C+GN~
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PASSWORD FOUND!!!!: pw == C-3P0
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TP 6 :
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Exercice 1
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Bonjour cher agent ! Votre prochaine mission, si vous
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l'acceptez bien sur, sera d'infiltrer le reseau
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souterrain ou se cache nos ennemis. Rendez-vous a
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Nantes le 29 avril pour le debut de votre mission
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Exercice 2
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v ubcfb osu ymoqsuu n cxqfj dqmfnu ub vjcfqu juz amqjmruz zmsscfusb bquflu auoquz hfszbms zwfba ju wusbms qusbqu ncsz ju vmo z uddmqvcfb n uxfbuq ju xusb wcoxcfz fj eczzc qcefnuwusb jc emqbu xfbquu no ijmv nuz wcfzmsz nu jc xfvbmfqu ecz czzul qcefnuwusb vueusncsb emoq uweuvauq kou z usrmoddqu us wuwu buwez kou jof os bmoqifjjms nu emozzfuqu ub nu zciju ju acjj zusbcfb ju vamo vofb ub ju xfuog bcefz c j osu nu zuz ugbquwfbuz osu cddfvau nu vmojuoq bqme xczbu emoq vu nuejmfuwusb fsbuqfuoq ubcfb vjmouu co woq ujju quequzusbcfb zfwejuwusb os usmqwu xfzcru jcqru nu ejoz n os wubqu ju xfzcru n os amwwu n usxfqms kocqcsbu vfsk csz c j uecfzzu wmozbcvau smfqu cog bqcfbz cvvusbouz ub iucog hfszbms zu nfqfruc xuqz j uzvcjfuq fj ubcfb fsobfju n uzzcpuq nu equsnqu j czvuszuoq wuwu cog wufjjuoquz uemkouz fj dmsvbfmsscfb qcquwusb cvboujjuwusb n cfjjuoqz ju vmoqcsb ujuvbqfkou ubcfb vmoeu ncsz jc ymoqsuu v ubcfb osu nuz wuzoquz n uvmsmwfu eqfzuz us xou nu jc zuwcfsu nu jc acfsu
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@@ -0,0 +1,8 @@
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import os
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from Crypto.Util.number import long_to_bytes
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from Crypto.Util.strxor import strxor
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FLAG = open("/home/nk/Documents/UTEC-Lic_ME_2024_2025/RSX112/RSX112-20-05-2025/flag.txt", "rb").read()
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key = os.urandom(4) * 20
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c = strxor(FLAG, key[:len(FLAG)])
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print(c.hex())
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